Tamil Nadu Public Service Commission is conducting a recruitment for the Posts of Bursar in Government Arts & Science Colleges and Colleges of Education. The total No. of vacancies for this job post is 05. Interested and eligible candidates can now apply for the posts by visiting the official website of TNPSC – tnpsc.gov.in by 10 December 2022.
This blog contains the important details of the recruitment. Check out the Vacancies, Age limit, Qualification, Pay scale, Selection process, Important Date, and Notification PDF links to apply.
Candidates can check the details of the recruitment below:
Contents
TNPSC Recruitment Eligibility Criteria –
Qualification :
Must have passed Post Graduate Degree in Public Administration Or Post Graduate Degree in Business Administration (MBA) with Specialization in Finance.
Age Limit :
18-32 years as on July 1, 2022. The upper age limit for reserved categories is 37 years.
Notification PDF –
Selection Process-
Selection will be made based on the marks obtained by the candidates in the CBT examination subject to the rule of reservation of appointments. After verification of the original certificates, the eligible candidates will be summoned for final selection through the counseling method.
Application Fee –
The applicants are required to pay the registration fee of Rs.150 and the exam fee of Rs.100.
Important dates –
Start of Online application:- 11/11/2022
End date of Online application:- 10/12/2022
Computer Based Test (CBT) – 10-03-2023
How to apply for TNPSC apprenticeship?
- Download official notification and read it carefully.
- Check eligibility.
- Go to TNPSC website.
- Check which post you want to apply based on eligibility.
- Fill application form.
- Check details of application form.
- Upload required documents.
- Pay the application fees.
- Submit the application.
- Check the TNPSC website/mail id for confirmation and any further news.
Important links for TNPSC application.
The links for various important information are given. The official www.tnpsc.gov.in website link is also given.
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